3a+[2+3(a-1)]=2(3a+4)

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Solution for 3a+[2+3(a-1)]=2(3a+4) equation:


Simplifying
3a + [2 + 3(a + -1)] = 2(3a + 4)

Reorder the terms:
3a + [2 + 3(-1 + a)] = 2(3a + 4)
3a + [2 + (-1 * 3 + a * 3)] = 2(3a + 4)
3a + [2 + (-3 + 3a)] = 2(3a + 4)

Combine like terms: 2 + -3 = -1
3a + [-1 + 3a] = 2(3a + 4)

Remove brackets around [-1 + 3a]
3a + -1 + 3a = 2(3a + 4)

Reorder the terms:
-1 + 3a + 3a = 2(3a + 4)

Combine like terms: 3a + 3a = 6a
-1 + 6a = 2(3a + 4)

Reorder the terms:
-1 + 6a = 2(4 + 3a)
-1 + 6a = (4 * 2 + 3a * 2)
-1 + 6a = (8 + 6a)

Add '-6a' to each side of the equation.
-1 + 6a + -6a = 8 + 6a + -6a

Combine like terms: 6a + -6a = 0
-1 + 0 = 8 + 6a + -6a
-1 = 8 + 6a + -6a

Combine like terms: 6a + -6a = 0
-1 = 8 + 0
-1 = 8

Solving
-1 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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